Balance De Energia

BALANCE DE MASA (PRACTICO)
M4=? (aire humedo)
ᶲ= 58%
W4=0,0274KgH2O/Kg AS
TBS= 40.14
TBH= 32.71

M4=? (aire humedo)
ᶲ= 58%
W4=0,0274KgH2O/Kg AS
TBS= 40.14
TBH= 32.71

CHORIZO FINALM2=12.99
T2=56 oC
(x2)H2O= 48.67%
(Y2)ST=51.33%

CHORIZO FINAL
M2=12.99
T2=56 oC
(x2)H2O= 48.67%
(Y2)ST=51.33%

Chorizo Inicial
T=27 oC
M1=17.41KgST=33.23%ST
H2O= 66.77%

Chorizo Inicial
T=27 oC
M1=17.41Kg ST=33.23%ST
H2O= 66.77%

AHUMADOR
AHUMADOR

Aire seco
TBS=35.85 oC
TBH= 28.42 M3=?
ᶲ= 100%
W3=0,0205KgH2O/KgAS
ᶲ= 60%

Aire seco
TBS=35.85 oC
TBH= 28.42 M3=?
ᶲ= 100%
W3=0,0205KgH2O/Kg AS
ᶲ= 60%

BALANCE TOTAL
M1+M3=M2+M417.41+M3=12.99+M4
M4= 4.72+M3

M4= 4.72 +750.6579
M4=754.999 Kg Aire húmedo

BALANCE PARCIAL DE AGUA
M1X1+ M3W3=M2X2+ M4W4
17.41(0,6677)+M(0,0205)=12.99(0,4867) +M4(0,0274)11.41(0.6677)+M3(0.0205)=12.99(0.4867)+M4(0.0274)
11.62+0.0205M3=6.32+0.0274(4.42+M3)
11.62+0.0205M3=6.32+0.121+0.0274M3
0.0205M3-0.0274M3=6.32+0.121-11.62
-0.0069M3= -5.179
M3=-5.179/-0.0069
M3= 750.579 Kg AS/1.5 h
Cp delproducto
Cp= % ST. Cp ST+ %H2O. Cp H20 (38®)
Cp= (0.5133)(3.31KJ/Kg C)+ (0.4867)(4.17KJ/Kg C)
Cp= 3.73 KJ/Kg C
BALANCE DE ENERGIA

QPS=M2.CpM2.ΔT
QPS= 12.99 Kg/h* 3.73 KJ/Kg C (56-27)
QPS=1405.13 KJ/1.5h * 1h/3600s
QPS= 0.260 KJ/S =Kw
QPS= 0.260 Kw * 1BHP/9.811 Kw
QPS= 0.0.265 BHP

CALOR LATENTE
QL= H2O evap * hfg 56C
QL= 4.42 * 2368.26 KJ/Kg
QL= 1046.71 KJ/1.5h * 1H/3600 SEG
QL=0.1938 Kw * 1BHP/ 9.811 Kw
QL= 0.0197 BHP
CALOR SENSIBLE DEL AIRE
CALOR SENSIBLE DEL AIRE
Qs aire= M3 (aire)* Cp M3* (T22-T1)
Qs aire= 750.579Kg/1.5h * 1.008 KJ/Kg C (105-28.42) * 1h/3600 seg...